Question

a ball of mass = 2 kg is fall from height of 9.8 m from the earth suface calculate the time to reach the ball at earth surface​

Answer 1

Answer:

Velocity before strice = u downward

Velocity after strike = V upward

u=

2gS

1

=

2×9.8×9.8

=9.8

2

m/s g = 9.8 taking

V=

2gS

2

=

2×4.9×9.8

=9.8m/s

change in momentum = impulse

mu−(−mv)=F×t

F=

t

1×9.8

2

+9.8

=

t

9.8(

2

+1)

=

0.1

9.8(1.41+1)

=98×2.41

=236.2N

Answer 2

Answer:

Velocity before strice = u downward

Velocity after strike = V upward

u=

2gS

1

=

2×9.8×9.8

=9.8

2

m/s g = 9.8 taking

V=

2gS

2

=

2×4.9×9.8

=9.8m/s

change in momentum = impulse

mu−(−mv)=F×t

F=

t

1×9.8

2

+9.8

=

t

9.8(

2

+1)

=

0.1

9.8(1.41+1)

=98×2.41=236.2N