A ball of mass 2 kg is projected at an angle of 60° with the horizontal. Find its kinetic energy at the highest point of its path if the velocity of projection is 4 m/s
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Class 11
>>Physics
>>Motion in a Plane
>>Projectile Motion
>>A body of mass 2 kg is proj...
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A body of mass 2 kg is projected from the ground with a velocity 20ms
−1
at an angle 30
o
with the vertical. If t
1
is the time in second at which the body is projected and t
2
is the time in second at which it reaches the ground, the change in momentum in kgms
−1
during the time (t
2
−t
1
) is
A
40
2
B
40
3
C
25
3
D
45
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Correct option is
B
40
3
Initial moment of the body in vertical upward direction
p
1
=mvcos30
o
=
2
3
mv
Final momentum of body in downward direction
p
2
=mvcos30
o
=
2
3
mv
Change in momentum
Δp=p
2
−(−p
1
)
=p
2
1
=
2
3
2
3
=
3
=
3
×2×20
=40
3
Explanation: