A ball of mass 2 kg is thrown from a height. What is the workdone by its weight in 2 seconds after the ball is dropped
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Hi!
m= 2kg
v=20m/s (g=10m/s)
Thus,
Work done= Gain in K.E = 1/2mv^2
= 1/2×2×20^2
=1×400
=400 joules / 400J
Hope it helps...!!!
m= 2kg
v=20m/s (g=10m/s)
Thus,
Work done= Gain in K.E = 1/2mv^2
= 1/2×2×20^2
=1×400
=400 joules / 400J
Hope it helps...!!!
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