A ball of mass 2 kg moving with velocity 3ms-1 collides with the another ball of mass 1 kg at rest and after collision the velocity of first ball becomes 2 ms-1. What is the velocity of second ball?
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According to law of conservation of momentum,
m1u1+m2u2=m1v1+m2v2
Therefore, 2(3)+1(0)=2(2)+1v
6+0=4+v
6-4=v
v=2 m/s
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