A ball of mass 2 kg released from a height of 20 m strikes the ground and rebounds to the height of 5m find the impulse deleivered to the ball by the ground.
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Explanation:
Velocity before strice = u downward
Velocity after strike = V upward
u=
2gS
1
=
2×9.8×9.8
=9.8
2
m/s g = 9.8 taking
V=
2gS
2
=
2×4.9×9.8
=9.8m/s
change in momentum = impulse
mu−(−mv)=F×t
F=
t
1×9.8
2
+9.8
=
t
9.8(
2
+1)
=
0.1
9.8(1.41+1)
=98×2.41=236.2N
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