A ball of mass 2 kg that has a diameter of 50 cm falls in the pool. Compute its volume of water displaced.
Answers
Answer:
: A ball of mass 2 kg having diameter of 50 cm falls in the swimming pool. Calculate its buoyant force and volume of water displaced. = 96 kg/m3. Hence volume of given body = Volume of displaced liquid.
Explanation:
please me Brinlet kar Dena please please please please
Answer:
Explanation:
Given: Mass of water, m = 2 kg,
Diameter of ball, d = 0.5 m r = 0.25 m
Volume of sphere V = 4343 ππ r3
= 4343 ππ 0.253
= 0.0208 m3
Hence the density is given by ρρ = MassVolumeMassVolume
= 2kg0.0208m32kg0.0208m3
= 96 kg/m3.
The force is given by F = mg. Hence buoyant force is
F = 2 kg ×× 9.8 m/s2 = 19.6 N
The archimedes formula is given by F = ρρ g Vdisp
Hence the Volume of displaced fluid is Vdisp = FρgFρg
= 19.696×9.819.696×9.8
= 0.0208 m3
Hence volume of given body = Volume of displaced liquid.