Question

A ball of mass 200 g falls from a height of 5 m. What is its kinetic energy when it just reaches the ground

Answer 1

$v = \sqrt{2gh} \\ v = \sqrt{2 \times 10 \times 5} \\ v = \sqrt{100 } \\ v = 10ms {}^{ - 1} \\ k.e = \frac{1}{2} \times m \times v {}^{2} \\ = \frac{1}{2} \times 200 \times 100 \\ 10000j$