A ball of mass 200 g falls from a height of 5 mtr.What is the kinetic energy when it just reaches the ground(g=9.8metres per second square) Please give answer.
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potential energy at the height
mgh= (200/1000)*9.8*5=9.8J
applying law of conversation of energy
PE=KE
9.8= 1/2*m*v²
9.8=1/2*0.2*v²
98=v²
v= 9.8m/s
It's KE= PE
mgh= (200/1000)*9.8*5=9.8J
applying law of conversation of energy
PE=KE
9.8= 1/2*m*v²
9.8=1/2*0.2*v²
98=v²
v= 9.8m/s
It's KE= PE
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