Question

A ball of mass 200 g is moving with a velocity of 10m/sec. If the error in measurement of velocity is 0.1% the uncertainty in its position is

Answer 1

Mass of Ball (m)= 0.2kg

Velocity of the Ball=10m/s

ΔV=0.1%=10×0.1100 = 0.01m/s

Hence, uncertainity in momentum,Δp=mΔV=0.2×0.01kg−ms−1=0.002kg−ms−1

Let change in position=Δx

So by uncertainty principle,Δp×Δx=h4π

Δx=h(4π×Δp)

Δx=6.64×10−34(4×3.14×0.002)m

Answer 2

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