a ball of mass 200 g is thrown vertically up with velocity of 30 m/s find its kinetic energy after 3 sec
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m=200 g=0.2 kg
u=30m/s
t=3s
g=-9.8 m/s^2
Then,
v=u+g*t
=30-9.8×3
=30-29.4
v=0.6 m/s
Now,
K.E.=1/2*m*v^2
=1/2×0.2×(0.6)^2
=0.036 J
Hope it helps u.
u=30m/s
t=3s
g=-9.8 m/s^2
Then,
v=u+g*t
=30-9.8×3
=30-29.4
v=0.6 m/s
Now,
K.E.=1/2*m*v^2
=1/2×0.2×(0.6)^2
=0.036 J
Hope it helps u.
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