Question

A ball of mass 200 g moving with a speed of 50 m/s is brought to rest by a player in 0.02 s. Then find the change in momentum of ball.

Answer 1

change in momentum =

p = m(vf-vi)

p= 1/5 (0-50) = -10 kg.m/s

Explanation:

Answer 2

Given :-

◉ A ball of mass 200 g or 0.2 kg moving with a speed of 50 m/s is brought to rest by a player in 0.02 s.

To Find :-

◉ Change in Momentum of the ball.

Solution :-

We know,

⇒ Change in Momentum = Mass × Change in velocity

⇒ ∆p = m∆v

⇒ ∆p = m(v - u)

Where, v = final velocity,

u = Initial velocity

Since the ball is brought to rest by the player, Hence the final velocity of the ball would be 0 m/s.

Now, We have

⇒ ∆p = (0.2 × 0 - 0.2 × 50)

⇒ ∆p = -10

⇒ ∆p = -10 kg. ms⁻¹

Hence, Change in Momentum of ball is -10 kg.ms⁻¹ which is in opposite direction of the ball.

Some Information :-

☛ Change in momentum per unit time is termed as Force, Its SI unit is Newton.

Force = ∆mv / ∆t

☛ Change in force per unit time is termed as Impulse, It is measured in Newton per second.

Impulse = ∆F / ∆t