A ball of mass 200 g moving with a velocity of 15m/s is broughtt to rest by a player in 0.05s .what is the impulse of the ball and average force applied by the player
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Answered by
4
Impulse = mass * change in velocity
= 0.2kg * (15m/s - 0)
= 3.0 kgm/s
Average Force = Impulse / Time
= 3.0kgm/s / 0.05s
= 60 N
= 0.2kg * (15m/s - 0)
= 3.0 kgm/s
Average Force = Impulse / Time
= 3.0kgm/s / 0.05s
= 60 N
Answered by
6
H e y a ! ! !
Here is the solution -:
➡ Impulse = mass × change in velocity
= 0.2kg × (15m/s - 0)
= 3.0 kgm/s
➡ Average Force = Impulse / Time
= 3.0kgm/s / 0.05s
= 60 N
#hope it helps !
Here is the solution -:
➡ Impulse = mass × change in velocity
= 0.2kg × (15m/s - 0)
= 3.0 kgm/s
➡ Average Force = Impulse / Time
= 3.0kgm/s / 0.05s
= 60 N
#hope it helps !
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