A ball of mass 200 gm travelling in a straight line with a speed of 15 metre per second along negative x axis is deflected by a bad an angle of 30 degree . If the speed of ball after deflection is 10 metre per second , find the Impulse of the ball.
Physics class 11th
Answers
Explanation:
Here , m=0.2kg
υix=−15m/s,υiy=0,υf=10m/s,0=30∘
υfx=υfcos30∘=103–√/2=53–√m/s
υfy=υfsin30∘=10×12=5m/s
Impulse, Ix=m(υfx−υix)=0.2(53–√+15)
=4.73Ns
Iy=m(υfy−υiy=0.2(5−0)=1.0Ns
∴ Net impulse on the ball, I=I2x+I2y−−−−−−√
(4.73)2+12−−−−−−−−−−√=4.83Ns.
Given info : A ball of mass 0.2 kg travelling in a straight line with a speed of 15 m/s along negative x-axis is deflected by a bat at an angle of 30°.
To find : if the speed of the ball after deflection is 10 m/s. the impulse in the ball is...
solution : mass of ball, m = 0.2 kg
initial velocity of ball, u = -15 i m/s
final velocity of ball, v = -10(cos30° i + sin30° j)
= -10(0.866 i + 0.5 j)
= -8.66 i - 5 j
impulse = change in linear momentum
= final linear momentum - initial linear momentum
= 0.2(-8.66i - 5j) - 0.2(-15 i)
= (1.732 + 3)i - j
magnitude of impulse = √{(4.732)² + (1)²}
= 4.83 Kgm/s
Therefore the impulse of the ball is 4.83 kgm/s.