A ball of mass 200 gram falls from a height of 5m.What is its kinetic energy when it just reaches the ground?(g=9.8 m/sec^2)
ti123488:
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height=5m.
mass=200g (0.2 kg)
g=9.8m/s^2
∴ potential energy=mgh
= 0.2*5*9.8
= 9.8 J
∵ P.E at the highest point= K.E at the lowest point (when it is just about to hit the ground)
∴ K.E energy will be= 9.8 J
hllo
YES
frnd?
yogita
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The sum of kinetic energy and potential energy is always constant.
When ball is at the height of 5 m, it has only potential energy which is = mgh
=0.2×10×5 = 10 J
(Mass in kg =0.2 kg , g=10)
When it reaches on ground,all its P.E converts in K.E
So,K.E when ball reaches to ground = 10 J
When ball is at the height of 5 m, it has only potential energy which is = mgh
=0.2×10×5 = 10 J
(Mass in kg =0.2 kg , g=10)
When it reaches on ground,all its P.E converts in K.E
So,K.E when ball reaches to ground = 10 J
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