A ball of mass 200 gram falls from a height of 5m what its kinetic energy when it just reach the ground? (g= 9.8 m/s sq
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h=5m
g=a=9.8
m=200g
v=?
u=0
one of the equations of motion
v^2-u^2=2×g×h
v^2= 2×5×9.8
v^2 =98
v= √98=9.89
I hope that you know
KE= 1/2×m×v^2
=1/2×200×98
=100×98
KE =9800
g=a=9.8
m=200g
v=?
u=0
one of the equations of motion
v^2-u^2=2×g×h
v^2= 2×5×9.8
v^2 =98
v= √98=9.89
I hope that you know
KE= 1/2×m×v^2
=1/2×200×98
=100×98
KE =9800
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