A ball of mass 200 gram moving with a velocity of 90 km per hour is stopped by a fielder in 0.5 second calculate the force applied by the fielder to stop the ball
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Answered by
20
Answer:
force is 10 N
Explanation:
m = 200 g = 0.2 kg ,
V = 90000/3600 m/s = 25 m/s
t = 0.5 s
F = ?
using 2nd law of motion
F = ma = m v/ t
F = 0.2 x 25 / 0.5
F = 10 N
Answered by
6
Answer:
10 Newton is the answer......
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