A ball of mass 200 grams and moving with a velocity 20 m per second is hit with a bat so that the ball rebounds with the same speed if the collision lasts for 0.1 second, 1.find the impulse delivered by the force 2.Average force with which the ball is hit
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Answer:
Given,
Mass, m=0.2kg
Final velocity, v
f
=40ms
−1
Initial velocity, v
i
=−20ms
−1
Change in momentum, ΔP=m(v
f
−v
i
)=0.2[40−(−20)]=12kgms
−1
Average force, F
av
=
Δt
ΔP
=
6×10
−3
12
=2000N
Hence, average force is 2000N
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0
Explanation:
2) m( vi- vf)
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