Question

A ball of mass 200g falls from 5cm.find the kinetic energy when reachs on ground ​

Answer 1

Answer:

0.1J

Explanation:

use kinetic energy formula with sign conversion

Answer 2

Explanation:

We Have :-

$A \: ball \: of \: mass \: 200 \: g \\ \\ \\ Distance \: = 5 \: cm$

To Find :-

$kinetic \: energy$

Solution :-

$When \: we \: take \: g \: = 10 \: m \: s^{ - 2} \\ \\ \\ Height \: = 5 \: cm \\ \\ \\ = 0.05 \: m \\ \\ \\ Mass \: = 200 \: g \\ \\ \\ = 0.2 \: kg \\ \\ \\ Potential \: energy \: = \: m \: g \: h \\ \\ \\ = 0.2 \times 0.05 \times 10 \\ \\ \\ 0.1 \: J \\ \\ \\ Potential \: energy \: at \: highest \: = \: Kinetic \: energy \: at \: lowest \\ \\ \\ Kinetic \: energy \: = 0.1 \: J \\ \\ \\ When \: we \: take \: g \: = 9.8 \: m \: s^{ - 2} \\ \\ \\ Height \: = 5 \: cm \\ \\ \\ = 0.05 \: m \\ \\ \\ Mass \: = 200 \: g \\ \\ \\ = 0.2 \: kg \\ \\ \\ Potential \: energy \: = \: m \: g \: h \\ \\ \\ = 0.2 \times 0.05 \times 9.8 \\ \\ \\ 0.098 \: J \\ \\ \\ Potential \: energy \: at \: highest \: = \: Kinetic \: energy \: at \: lowest \\ \\ \\ Kinetic \: energy \: = 0.098 \: J$