A ball of mass 200g falls from a height 5m. What is its keinetic energy when it just reaches rhe ground (g=9.8m/p
Answers
Answered by
1
Answer...is 9.8
Explanation:
Answer:formula is...1/2 mv2...so we can solve easily by using formula-
2as=v2-u2
2×9.8×5=v2
V2=98
1/2mv2=9.8
Answered by
45
Given :-
- Mass of the ball (m) = 200 g
- Height (h) = 5 m
- Acceleration due to gravity (g) = 9.8 m/s²
To Find :-
- kinetic energy of the ball when it reaches the ground = ?
Solution :-
First convert the unit of the mass of ball from gram to kilogram :
- → Mass of ball = 200 g
- → Mass of ball = (200) ÷ (1000)
- → Mass of ball = 2 ÷ 10
- → Mass of ball = 0.2 kg
Hence,the mass of the ball is 0.2 kg.
According to the Question Now :-
Finding potential energy at higest point :
- → Potential energy = mass × Acceleration due to gravity × Height
- → Potential energy = 0.2 × 9.8 × 5
- → Potential energy = 1.96 × 5
- → Potential energy = 9.8 J
Hence,the potential energy of ball is 9.8 J.
- As we know that, the Potential energy at the highest point is equal to the Kinetic energy at the lowest point.
- Hence,from the above statement we can conclude that the Kinetic energy of the ball when it reaches the ground will be 9.8 J.
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