A ball of mass 200g is moved with 20m/s and decrease to 10m/s in 5s due to air friction so force of friction due to air is
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Answer:-
Newton's 3rd Law of Motion: Every action has an opposite and equal reaction which acts on both the objects.
∴ The air will also provide the same magnitude of force to the ball. But the symbol would be (- ve).
Given:-
- m = 0.2 kg
- u = 20 m/s
- v = 10 m/s
- t = 5 s
We know,
F = ma
where,
- F = Force,
- m = Mass &
- a = Acceleration.
Also,
a = (v - u)/t
where,
- v, u = Final and Initial velocities respectively,
- t = Time taken.
Thus,
F = m(v - u)/t
→ F = (0.2 kg)[(10 - 20) m/s]/5 s
→ F = (0.2 kg)(- 10 m/s)/5s
→ F = (0.2 kg)(- 2 m/s²)
→ F = - 0.4 kg m/s²
→ F = - 0.4 N
(Force acting on the body at the opposite side of it's motion.)
Thus, air provided a force of 0.4 N.
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