Question

A ball of mass 200g moving with a velocity of 90 km per hour is stopped by a fielder in 0.5 seconds calculate the force applied by the fielder to stop the ball.

Answer 1

Hey there..!

refer to the image attached.

(-ve sign indicates, opposing force.)

HOPE THIS HELPS YOU
BE BRAINLY

Answer 2

Answer:

10 N

Explanation:

Here,

Mass = “m” = 200g

= ( 200 ÷ 1000) kg

= 0.2 kg

{As 1 gram (g) = 1 ÷ 1000 Kilogram (kg)}

Initial Velocity = “u” = 90 km/hr

= (90 × 5/18) m/s

= 25 m/s

Final Velocity = “v” = 0 m/s

Time Taken = “t” = 0.5 s

Force = “F” = ??

Now,

Using Second Law of Motion,

F = m*a

= 0.2*{(v-u)÷t}

= 0.2*{(0-25)÷0.5}

= 0.2*{(-25)÷0.5}

= 0.2*(-50)

= (-10.0)

= (-10) N

Hope this helps you!!