a ball of mass 200g slows down from 10 m/s to 2m/s .Find change in momentum
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Answer:
Initial velocity of the ball, u=−10 ms
−1
(- sign shows the opposite direction)
Final velocity of the ball, v=5 ms
−1
Mass of the ball, m=200 g=0.2 kg
Net change in the momentum of the ball, ΔP=P
f
−P
i
ΔP=mv−mu=m×5−m×(−10)
∴ΔP=15×m=15×0.2=3 kg m s
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