a ball of mass 200g strikes a wall with speed 10m/s and renounces with speed 6m/s . what is the change in momentum of the ball
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Answered by
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Answer:
answer is -3Ns
Step-by-step explanation:
Mass of ball(m)=200g=0.2kg
Initial velocity of ball(u)=10ms −1
Final velocity of ball(v)=5ms −1
Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms −1
=−3 Ns
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Answer:
Answer Is Wrong If you don't know so why Giving answer
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