Question

A ball of mass 200gm moving with a speed of 5ms is hit a bat so that the ball returns with a speed of 10 ms. Work done by the bat on the ball is?​

Answer 1

Answer:

Mass of ball(m)=200g=0.2kg

Initial velocity of ball(u)=10ms  

−1

 

Final velocity of ball(v)=5ms  

−1

 

Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms  

−1

=−3 Ns