A ball of mass 200kg falls from a height of 5m .what is it,s kinetic energy when it just reaches the ground .....Hint gravity is 9.8m/s
deepak70:
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Answered by
1
Using equation of motion
v=?
u=0
g= 9.8
h=5
V2 - u2 = 2gh
v2 -0 = 2×9.8×5
v2= 98
v= root 98 m/s
Now using the relation
Kinetic energy = 1/2 m v2
= 1/2×200×98
= 100×98
= 9800 Joule
v=?
u=0
g= 9.8
h=5
V2 - u2 = 2gh
v2 -0 = 2×9.8×5
v2= 98
v= root 98 m/s
Now using the relation
Kinetic energy = 1/2 m v2
= 1/2×200×98
= 100×98
= 9800 Joule
hope it helps
Answered by
0
ep=mgh
ep=200*5*9.8=9800
ep=200*5*9.8=9800
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