a ball of mass 250 grams moving with the speed of 2 m/se hits the wall normally.It rebounces with the same speed.If the two were contact for 0.001 sec the average force exered by wall on the ball
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grandhesomesh:
options are a)4*10^-3 N b) 2*10^-3 N c)10^3 N d) 10^-2 N
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the ball rebounds with speed but in opposite direction .
Hence , total change in momentum =mv-(-mv)=2mv=(2)(.01)(5)=0.1from newton’s second law force=change in momentum per unit time.force=2mv/0.01=0.1/0.01=10N ans.
Hence , total change in momentum =mv-(-mv)=2mv=(2)(.01)(5)=0.1from newton’s second law force=change in momentum per unit time.force=2mv/0.01=0.1/0.01=10N ans.
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