A ball of mass 2kg falls from rest. What will be its kinetic energy during the fall at the end of 2s?(Take g=9.8 m s^-2).
AmeyaShri123:
Its answer is 384.16 J in my book. Please solve quickly.
Answers
Answered by
2
u = 0
v = ?
g = 9.8 m/s^2
t = 2s
we know
v- u = gt
v - 0 = 9.8 x 2
v = 19.6
___________________________
now
m = 2 kg
v = 19.6 m/s
KE
= 1/2 x mv^2
=( 1/2 x 2 x 19.6^2 ) J
= 384.16 J
v = ?
g = 9.8 m/s^2
t = 2s
we know
v- u = gt
v - 0 = 9.8 x 2
v = 19.6
___________________________
now
m = 2 kg
v = 19.6 m/s
KE
= 1/2 x mv^2
=( 1/2 x 2 x 19.6^2 ) J
= 384.16 J
Its ans=384.16 J as given in textbook.
Please solve the question correctly.
Answered by
0
Hey there !
Initial velocity = u = 0
Final velocity = v
g = 9.8 m/s²
time = t = 2 sec
v - u = gt
v = 9.8 x 2
v = 19.6 m/s
mass = m = 2 kg
v = 19.6 m/s
Kinetic energy = 1/2 mv²
= 1/2 x 2 x 19.6 x 19.6
= 384.16 J
Initial velocity = u = 0
Final velocity = v
g = 9.8 m/s²
time = t = 2 sec
v - u = gt
v = 9.8 x 2
v = 19.6 m/s
mass = m = 2 kg
v = 19.6 m/s
Kinetic energy = 1/2 mv²
= 1/2 x 2 x 19.6 x 19.6
= 384.16 J
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