Question

a ball of mass 2kg from a height of 5 makers. what is its kinetic energy when huts rashes the ground​

Answer 1

${\pink{\underline{\underline{\purple{\textsf{\textbf{Correct question : }}}}}}}$

A metal ball of mass 2kg is allowed to fall freely from rest from a height of 5m above the ground $\rm (Take g=10ms^{−2}).$ What is the kinetic energy of the ball just before it hits the ground?

${\pink{\underline{\underline{\purple{\textsf{\textbf{Answer : }}}}}}}$

➡ 100joule.

${\pink{\underline{\underline{\purple{\textsf{\textbf{Explanation : }}}}}}}$

Given that, A ball of mass 2kg is allowed to fall freely from rest to a height of 5metres.

Using the formula :

❃ K. E. (kinetic energy) = mgh

Where,

m (mass) = 2kg

g (acceleration due to gravity) = $\rm {10ms}^{2}$

h (height) = 5 metres.

Procedure :

➡ K. E. = mgh

➡ K. E. = 2*5*10

➡ K. E. = 100 joule.

${\pink{\underline{\underline{\purple{\textsf{\textbf{Hence, the kinetic energy of the ball is 100joule. }}}}}}}$

${\blue{\underline{\underline{\green{\textsf{\textbf{Additional info : }}}}}}}$

This is the total energy as K.E is zero when the ball is at maximum height that is when it is at 5 m. Hence when the ball reaches the ground P.E becomes zero because of zero height.At this point,the total energy is equal to the K.E that is K.E=100J.

Answer 2

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Given that, A ball of mass 2kg is allowed to fall freely from rest to a height of 5metres.

Using the formula :

❃ K. E. (kinetic energy) = mgh

Where,

m (mass) = 2kg

g (acceleration due to gravity) = \rm {10ms}^{2}10ms

2

h (height) = 5 metres.

Procedure :

➡ K. E. = mgh

➡ K. E. = 2*5*10

➡ K. E. = 100 joule.