Question

A ball of mass 2kg is dropped from a height of 2m. What's it's kinetic energy, when it touches the ground?

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Answer 1

Mass (m) = 2Kg

Height (H) = 2m

When placed at a height of 2m.

The potential energy stored = Mgh

=(2)(10)(2) =40J

According to Work Energy Principle,

mgh=mv^2/2

Therefore,

(10)(2)(2) =v^2

Therefore, v = (2)root (10)

Or v=6.32 m/s

Answer 2

s=2m

m=2kg

u=0m/s

a=10m/s2

v=?

2as=v2-u2

2*10*2=v2-02

v=√40

=6.32m/S

KE=1/2mv2

=1/2*2*√40

=√40

=6.32J