a ball of mass 2kg is dropped from a height .What is the wlrk done its weight 2sec after the ball is dropped?
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Mass of ball, m=10 kg
Height, h=10 m
Potential energy of ball at the maximum height=mgh=10 x 10 x 10=1000 J
Kinetic energy of ball when it reaches ground=1/2 m v2=1/2 x 10 x v2
Now, according to the conservation of energy,
P.E=K.E
1000=1/2 x 10 x v2
v=14.14 m/s
Height, h=10 m
Potential energy of ball at the maximum height=mgh=10 x 10 x 10=1000 J
Kinetic energy of ball when it reaches ground=1/2 m v2=1/2 x 10 x v2
Now, according to the conservation of energy,
P.E=K.E
1000=1/2 x 10 x v2
v=14.14 m/s
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