Question

A ball of mass 2kg is kept on a tower of height 30m. Find its potential energy at this point. If it is allowed to fall freely, find its

kinetic energy when it just touches the ground?

Answer 1

m=2kg

h=330m

P.E.=mgh

=2×9.8(g=9.8m/s)×330

=6468J

K.E.=1/2 mv square

kinetic energy is equals to half MV square we can put the value of V square =6468

KE is equals to 1 / 2 × 2 × 6468 we can cancel 2 by 2 and the kinetic energy is equal to 6 4 6 8 J.

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Answer 2

Answer: P. E =mgh

= 2x10x30

= 600J

K. E = 1/2mv square

V Square - U square =2as

V Square =2as +u square

V square =

Har har mahadev