A ball of mass 2kg is set in a straight line motion. It strikes a second, stationary ball of mass 5kg. The velocity of the first ball, when it strikes the second ball is 20m/s. The first ball comes to a complete halt as a result of the collision. The two balls are in contact for 0.01 seconds. Calculate the force applied to the second ball by the first ball.
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Answer:4000N
Explanation:
Mass of 1st ball(m1)=2kg
Mass of 2nd ball(m2)=5 kg. Velocity of 1st ball(v1)=20m/sec
Velocity of 2nd ball be v2 m/sec
According to the law of conservation of linear momentum
m1*v1=m2*v2
=>2*20=5*v2
=>v2= 2*20/5
=>v2= 8 m/sec
Momentum of 2nd ball before collision(Pi)= 0 kgm/sec
Momentum of 2nd ball after collision(Pf)= (5*8)kgm/sec
Force applied=(Pf-Pi)/time
=(40-0)/0.01
=4000N (ans)
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