Question

a ball of mass 2kg is thrown up with a speed of 10m/s. find the kinetic energy of the ball at the time of throwing. also find the potential energy of the ball at the highest point?

Answer 1

kinetic energy= 1/2 mv^2
m= 2kg
v= 10m/s
1/2×2×10
= 10joule

Answer 2

The ball has 100 J of kinetic energy at the moment of throwing and 100 J of potential energy at its highest point.

K = 0.5 * m * $v^{2}$,

where m is the ball's mass and v is its velocity, can be used to calculate the kinetic energy of the ball at the moment of throwing.

When the given values are substituted, we obtain

K = 0.5 * 2 kg * (10m/s)2 = 100 J.

The ball, therefore, has 100 Joules of kinetic energy at the moment of throwing.

At its highest point, the ball's potential energy is equal to the effort required to lift it against gravity.

Potential energy is calculated using the equation P.E. = mgh,

where m is the ball's mass, g is its gravitational acceleration, and h is its height above a reference point.

The formula h = ($v^{2}$)/(2g),

where v is the initial velocity and g is the acceleration brought on by gravity, can be used to determine the height at its highest point, which is equal to the highest height the ball has ever reached. When the given values are substituted, we obtain

h = (10m/s)2/(2*9.8m/s) = 5.1m.

Therefore, P.E = 2 kg * 9.8 m/s2 * 5.1 m = 100 J is the ball's potential energy at its highest point.

For more such questions on potential energy: https://brainly.in/question/45839166

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