Physics, asked by sg7681265, 18 days ago

a ball of mass 2kg is thrown up with a speed of 15m/s find the kinetic energy of the ball at the time of throwing (g=10m/s²)​

Answers

Answered by ImperialGladiator
25

Answer:

225 joules

Explanation:

Question says that,

A ball of mass 2kg is thrown upwards with a speed of 15m/s.

Find the kinetic energy.

We know that,

→ K.E. = ½mv²

Where,

  • m’ denotes the mass of the ball.
  • v is the velocity

Hence,

→ K.E. = ½*2*(15)²

→ K.E. = 1*225

→ K.E. = 225 J

Kinetic energy of the ball is 225 joules.

__________________________

Answered by StarFighter
37

Answer:

Given :-

  • A ball of mass 2 kg is thrown up with a speed of 15 m/s.

To Find :-

  • What is the kinetic energy of the ball at the time of throwing.

Formula Used :-

\clubsuit Kinetic Energy Formula :

\bigstar \: \: \sf\boxed{\bold{\pink{K.E. =\: \dfrac{1}{2}mv^2}}}\: \: \: \bigstar\\

where,

  • K.E. = Kinetic Energy (J)
  • m = Mass (kg)
  • v = Velocity (m/s)

Solution :-

Given :

  • Mass = 2 kg
  • Velocity = 15 m/s

According to the question by using the formula we get,

\dashrightarrow \sf\bold{\blue{K.E._{(Ball)} =\: \dfrac{1}{2}mv^2}}\\

By putting those values we get,

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{1}{2} \times 2 \times (15)^2\\

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{1}{2} \times 2 \times (15 \times 15)\\

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{1}{2} \times 2 \times 225\\

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{1}{2} \times 450\\

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{1 \times 450}{2}

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{\cancel{450}}{\cancel{2}}

\dashrightarrow \sf K.E._{(Ball)} =\: \dfrac{225}{1}

\dashrightarrow \sf\bold{\red{K.E._{(Ball)} =\: 225\: Joules}}\\

\footnotesize \sf\bold{\underline{\purple{\therefore\: The\: kinetic\: energy\: of\: the\: ball\: at\: the\: time\: of\: throwing\: is\: 225\: Joules\: .}}}\\

\\

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