Question

A ball of mass 2kg thrown vertically up with a velocity 20 ms.
1.The maximum height reached by the ball

2.The time taken by the ball to reach the same point of projection

3.The distance covered by the ball during the first second in the downward journey
a) 20 m
b) 25 m
c) 5 m
d) 10 m
solution plz​

Answer 1

Answer:

1. nearly 20m

Explanation:

1. v^2=u^2+2as

v=0;u=20 a=g= 10m/s^2

hence s= 20m

2. v-u=at

t= 2 sec..