A ball of mass 3 kg is suspended by a light string and pulled by a horizontal force F so that the string makes an angle of 60° with the vertical. The horizontal force Find kg wt
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Given :-
Mass of body = 3 Kg
Horizontal force = F
Angle = 30°
Solution :-
F = T cos (30°)
mg = T sin (30°)
√3 g = T √3 / 2
T = 2 x g = 2 x 10 = 20 N
F = T x 1/2
F = 20 x 1/2 = 10 N
Hence the tension in the string is 20 N and the force is 10 N.
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