Question

A ball of mass 3 kilograms begins falling with gravity of 10 meters per second squared. How many meters does it fall in 8 seconds?

Answer 1

Given a ball starts falling with gravitational acceleration of 10 m/s².

To find how many metres it will fall in 8 seconds.

Since the body starts falling

=> u = 0 m/s

g given = 10 m/s²

t = 8 seconds

We know that,

s = ut + 1/2 at²

=> s = 0 × 8 + 1/2 × 10 × 8²

=> s = 5 × 64

=> s = 320 metres.


It fell 320 metres in 8 seconds.

Answer 2

According to Question :-

Gravitational acceleration of 10 m/s².

To Find :-

Fall in 8 seconds.

Hence the body starts falling

=> u = 0 m/s

g = 10 m/s² (Given)

t = 8 seconds

By the equation of motion :-

$s=ut +\frac{1}{2} at^{2}$

$s=0*8+\frac{1}{2} *10*(8)^{2}$

=> s = 5 × 64

=> s = 320 m

It will fell  in 320 metres in 8 seconds.