Question

A ball of mass 4 kg and density 4000 kg/m3 is completely immersed in water of density 1000 kg/m3. Find the buoyant force on the ball.

Answer 1

Mass of ball m = 4 kg
Density of ball ρ = 4000 kg/m3
Volume of the ball V = m/ρ
= 4/4000 m^3
= 10-3 m^3.
Buoyant force or upthrust acting on the ball = Volume of water displaced x density of water x acceleration due to gravity
= 10-3 m^3 x 1000 kg/m^3 x 9.8 m/s^2
= 9.8 kg. m/s^2
= 9.8 N.

Answer 2

Aɴꜱᴡᴇʀ

Buoyant Force=10N

_________________

Gɪᴠᴇɴ

Weight of ball = 4 kg

Density of ball = 4000 kgm³

Density of water= 1000 kgm³

_________________

ᴛᴏ ꜰɪɴᴅ

Buoyant force?

_________________

Sᴛᴇᴘꜱ

The buoyant force is given by

$\large \sf \orange{f = pgv}$

$\large \sf{}f = \frac{4}{4000} \times 10 \times 1000 \\ \\ \large \pink{ \dashrightarrow{} \tt{}f = \huge \red{10n}}$

Additional information:-

Buoyant : Buoyant force is an upward force exerted by a fluid, which opposes the weight of an object in the fluid. Objects immersed in water observes a loss in weight due to the buoyant force.

_________________

$\huge{\mathfrak{\purple{hope\; it \;helps}}}$