A ball of mass 4 kg is pressed against a spring and released vertically with a velocity of 5 m/s. If 20% of the energy is lost in overcoming air friction then the maximum height attained by the ball is:
1.25 m
1.75 m
1 m
2 m
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Answer:
h=1 m
Explanation:
KE=1/2×m×v²
=)40
PE=mgh
kindly refer the pic
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