Question

A ball of mass 4 kg is thrown vertically upwards from the ground with the initial velocity of 40 m/sec. Find the change in potential energy of the ball when it reaches maximum height. (Neglect air friction)

Answer 1

mass = 5 kg

u = -10 m/s

v = 0 m/s

g = -10 m/s²…for this case

2as = v² – u²

2(-10)(s) = -100

S = -100/-20

S = 5 m

Now,

Potential energy = mgh

P.E = 5 * 10 * 5

P.E = 250 J

Now, Kinetic energy 

K.E = 1/2mv²

K.E = ½*5*100

K.E = 5*50


K.E = 250 J

 I hope it helps