a ball of mass 400 g is thrown vertically upward find its initial momentum
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momentum=mass ×Acceleration
400×10=4000
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# Answer- I = -2m√(gh)
# Explaination-
When an object is thrown vertically upwards at height b and falls down,
displacement s = 2h
acceleration a = -g
By Newton 3rd kinematic eqn,
v^2 = u^2 + 2as
0 = u^2 + 2(-g)(2h)
u = √(4gh)
Impulse = Change in momentum
I = m(v-u)
I = m[0-√(4gh)]
I = -2m√(gh)
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