Question

a ball of mass 4kg is thrown bwith the speed of 5 m/s and stops after 5 sec what is the distance covered by ball on the ground.​

Answer 1

Answer:

Given, m

1

=4kg u

1

=u (say) m

2

=m & u

2

=0 (at rest)

also, v

1

=u/4 and collision is elastic

From collision theory,

v

1

=(

m

1

+m

2

m

1

−m

2

)u

1

+(

m

1

+m

2

2m

2

)u

2

Put values

4

u

=(

4+m

4−m

)u+0⇒4+m=4(4−m)⇒m=

5

12

=2.4kg (Ans)

hope this will help u ❤️