a ball of mass 50 g is dropped from a height of 20 m a boy on the ground hits the ball vertically upwards with the bat with an average force of 200 N so that it attains a vertical height of 45 m. the time for which the ball remains on contact with the bat is
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WE CAN FIND IT USING IMPULSE MOMENTUM THEOREM.
F*T=m(V-U
U=-√2GH=-√2*10*20=-2M/S
V=√2Gh=√2*10*45=30M/S
200 *T=.O5(30+20
T=.0125 SEC
I HOPE THIS HELPED U...
F*T=m(V-U
U=-√2GH=-√2*10*20=-2M/S
V=√2Gh=√2*10*45=30M/S
200 *T=.O5(30+20
T=.0125 SEC
I HOPE THIS HELPED U...
goldie1:
thanks alot but i didnt understand it sorry..could u explain it with a different method
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