Question

A ball of mass 50 g is thrown vertically upwar
with an initial velocity 20 m s-1. Calculate :
(i) the initial kinetic energy imparted to the bal
ii) the maximum height reached if air friction
neglected, and
iii) the maximum height reached if 40% of time
initial energy is lost against the air friction.​

Answer 1

Answer:

the photo above is the answer of I)

2) Given that,

m=0.05 and v=20m/s

1

Maximum potential energy at highest point= Initial kinetic energy at the bottom point

∴Maximum potential energy =

2

1

mv

2

=

2

1

×0.5×20×20

=

2

200

=100J

3) Given that,

m=0.05 and v=20m/s

1

Maximum potential energy at highest point= Initial kinetic energy at the bottom point

∴Maximum potential energy =

21 mv 2

= 21×0.5×20×20= 2200

=100J

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Answer 2

Answer:

2) Given that,

m=0.05 and v=20m/s

1

Maximum potential energy at highest point= Initial kinetic energy at the bottom point

∴Maximum potential energy =

2

1

mv

2

=

2

1

×0.5×20×20

=

2

200

=100J

3) Given that,

m=0.05 and v=20m/s

1

Maximum potential energy at highest point= Initial kinetic energy at the bottom point

∴Maximum potential energy =

21 mv 2

= 21×0.5×20×20= 2200

=100J

hope this helps

plz mark me as brainliest answer

Explanation: