Question

a ball of mass 50 g is thrown vertically upward with an initial velocity of 20m/s calculate.inital KE , max height reached ,max height reaxched if 40% energy lost

Answer 1

Answer:

Explanation:

m=0.05 and v=20m/s  

1

 

Maximum potential energy at highest point= Initial kinetic energy at the bottom point

∴Maximum potential energy =  

2

1

​  

mv  

2

 

=  

2

1

​  

×0.5×20×20

=  

2

200

​  

 

=100J

​  

 

Answer 2

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Mass of ball = 50g = 0.05 kg

Initial velocity = u = 20m/s

Initial KE = 1/2 mu²

                = 1/2 * 0.05 * 20²

                = 1/2 * 0.05 * 400

                 = 1/2 * 5 * 4

                 = 10J

The KE is getting converted to PE  hence,

KE = PE

1/2 mu² = mgh

10 = 0.05 * 10 * h

0.05h = 10/10

h = 1/0.05 = 20m

Only (100-40)% = 60% of the KE isconverted to PE,

60% of KE = PE

60/100 * 1/2 mu² = mgh

60/100 * 10 = 0.05 * 10 * h

0.05h = 6/10

h = 6/0.5

h = 12m

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