Question

A ball of mass 50 gram is dropped from a height of 20 m a boy on the ground hits the ball vertically upwards with a bat with an average force of 200 Newton so that it attains a vertical height of 45m the time for which the ball remain in contact with the bat is

Answer 1

Hey mate!

The final velocity after falling 20 m is V² =  (0)² + 2(10)(20)

==> v = √400 = 20m/s

The ball, after hit by the bat travels for 45m upwards.

So, V = 0 at 45m above the ground.

==> 0 = u² + 2 (-10)(45)

==> u = √900 = 30m/s

The force with which the bat hits the ball is 200N = (m)(a)

==> a = 200/(50 × 10⁻³) = 4000m/s²

As, acc. = Δ Velocity / time

==> time of contact = (30) - (-20) / (4000)

                                = 50 / 4000

time of contact is hence = 1/80 seconds (or) 0.0125 seconds.

If the answer is correct, please mark me brainliest:))