Question

a ball of mass 50 grams is shot vertically upwards from a gun of mass 1000 grams. The gun is fixed to a stand which allows the gun to recoil. The ball fell on the ground after 10 seconds. Find
a) how much height the ball reached
b) it's velocity when the ball reached the ground
c) position of the ball after 7 seconds
d) the energy used by the gun to shoot the ball vertically
e) the initial velocity of recoiling gun
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Answer 1

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Here,

Mass of the gun, M = 100 kg

Mass of the ball, m= 1 kg

Height of the chiff, h= 500 m

g = 10ms

−2

Time taken by the ball to reach the ground is

t=

g

2h

=

10ms

−1

2×500m

Horizontal distance covered = ut

∴400=u×10

Where u is the velocity of the ball.

u=40 ms

−1

According to law of conservation of linear momentum, we get,

0=Mv+mu

v=−

M

mu

=−

100kg

(1kg)(40ms

−1

)

=−0.4ms

−1

-ve sign shows that the direction of recoil of the gun is opposite to that of the ball.

Answer 2

Explanation:

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