Question

a ball of mass 500 g is dropped from a height of 500 m. what is the momentum of the ball

Answer 1

Answer:

P=50

Explanation:

P= mv

Max height H= u^2/2g

500 = U^2/20

U^2= 500×20= 10000

U= 100m/s, m=500g=500×10^-3kg

Momentum p= mass×velocity= 500×10^- 3×100= 50

Answer 2

Explanation:

The answer is in attachment

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