Physics, asked by premgangar, 5 months ago

A ball of mass 500 g is moving with a velocity of 50 m s-1. The ball is brought to rest by applying a constant force for 0.2 s. Calculate the force applied.

Answers

Answered by nidhikhandelwal655
0

Answer:

force=?

force =mass × acceleration

Explanation:

acceleration=v/t...

50/0.2=250m/s2

force =m×a

500/1000×250...

u should find answer urself..

Answered by Anonymous
2

AnswEr :

  • Mass (m) = 500g = 0.5 kg
  • Initial velocity (u) = 50 m/s
  • Final velocity (v) = 0 m/s
  • Time (t) = 0.2s

Force : A push or pull acting on a body, which may or may not leads to change physical state.

\\ \longrightarrow \tt{F\ =\ ma} \\ \\ \\ \longrightarrow \tt{F\ =\ m\ \times\ \dfrac{v\ -\ u}{t} \; \; \; \; \; \; \; \; \bigg[\because\ a\ =\ \dfrac{v\ -\ u}{t} \bigg]} \\ \\ \\ \longrightarrow \tt{F\ =\ 0.5\ \times\ \dfrac{0\ -\ 50}{0.2}} \\ \\ \\ \longrightarrow \tt{F\ =\ 0.5\ \times\ \dfrac{-50}{0.2}} \\ \\ \\ \longrightarrow \tt{F\ =\ 0.5\ \times\ -250} \\ \\ \\ \large \longrightarrow \underline{\boxed{\frak{F\ =\ -125\ N}}}

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