Question

A ball of mass 500 g is moving with a velocity of 50 m s-1. The ball is brought to rest by applying a constant force for 0.2 s. Calculate the force applied.​

Answer 1

..Question..

A ball of mass 500 g is moving with a velocity of 50 m s-1. The ball is brought to rest by applying a constant force for 0.2 s. Calculate the force applied.

..Answer..

Given here ,

ㅤㅤ➪ Initial velocity ( u ) = 50 m/s

ㅤㅤ➪ Final velocity ( v ) = 0 m/s

ㅤㅤ➪ Time ( t )ㅤㅤㅤㅤ = 0.2 sec

ㅤㅤ➪ Mass ( m )ㅤㅤㅤ = 500 g / 0.5 kg

☯︎ We have to find ➪ Force Applied

At first ,

♧︎︎︎ We have to find accⁿ [ accⁿ = acceleration ]

•°• Formulas to calculate accⁿ ➪

• a = ( v - u ) / t
• v = u + at

Where ,

ㅤㅤㅤ➪ v = final velocity

ㅤㅤㅤ➪ u = initial velocity

ㅤㅤㅤ➪ a = acceleration

ㅤㅤㅤ➪ t = time taken

♧︎︎︎ Using second formula by putting values :

ㅤㅤ➪ v = u + at

ㅤㅤ➪ 0 = 50 + a × 0.2

ㅤㅤ➪ 0 - 50 = 0.2a

ㅤㅤ➪ - 50 = 0.2a

ㅤㅤ➪ 0.2a = - 50

ㅤㅤ➪ a = - 50 / 0.2

ㅤㅤ➪ a = - 250

•°• The acceleration is = - 250 m/s²

∵ We know that ✈︎

ㅤㅤ➪ F = mass × accⁿ

ㅤㅤ➪ F = m a

ㅤㅤ➪ F = 0.5 × ( - 250 )

ㅤㅤ➪ F = - 125

•°• Force Applied = - 125 N

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ♧︎︎︎ N = Newton ✓

_____________________

Give a look here ,

• FORMULAS :
• v = s / t
• v = u + at
• a = ( v - u ) / t
• s = ut + 1/2 at²
• v² - u² = 2as
• F = m a
• F = m g

ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂

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