Chemistry, asked by yrthvvb, 4 months ago

A ball of mass 500 g is moving with a velocity of 50 m s-1. The ball is brought to rest by applying a constant force for 0.2 s. Calculate the force applied.​

Answers

Answered by BRAINLYxKIKI
116

..Question..

A ball of mass 500 g is moving with a velocity of 50 m s-1. The ball is brought to rest by applying a constant force for 0.2 s. Calculate the force applied.

..Answer..

Given here ,

ㅤㅤ Initial velocity ( u ) = 50 m/s

ㅤㅤ Final velocity ( v ) = 0 m/s

ㅤㅤ Time ( t )ㅤㅤㅤㅤ = 0.2 sec

ㅤㅤ Mass ( m )ㅤㅤ = 500 g / 0.5 kg

☯︎ We have to find Force Applied

At first ,

♧︎︎︎ We have to find acc [ acc = acceleration ]

° Formulas to calculate acc

  • a = ( v - u ) / t
  • v = u + at

Where ,

ㅤㅤ v = final velocity

ㅤㅤ u = initial velocity

ㅤㅤ a = acceleration

t = time taken

♧︎︎︎ Using second formula by putting values :

ㅤㅤ v = u + at

ㅤㅤ 0 = 50 + a × 0.2

ㅤㅤ 0 - 50 = 0.2a

ㅤㅤ - 50 = 0.2a

ㅤㅤ 0.2a = - 50

ㅤㅤ a = - 50 / 0.2

ㅤㅤ a = - 250

° The acceleration is = - 250 m/

We know that ✈︎

ㅤㅤ F = mass × acc

ㅤㅤ F = m a

ㅤㅤ F = 0.5 × ( - 250 )

ㅤㅤ F = - 125

° Force Applied = - 125 N

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ♧︎︎︎ N = Newton

_____________________

Give a look here ,

  • FORMULAS :
  • v = s / t
  • v = u + at
  • a = ( v - u ) / t
  • s = ut + 1/2 at²
  • v² - = 2as
  • F = m a
  • F = m g

ㅤㅤ ʙʀɪɴʟʏ×ɪɪ

ㅤㅤ

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